Triangle PQR has vertices P(–3, –1), Q(–3, –3), and R(–6, –2). The triangle is rotated 90° counterclockwise using the origin as the center of rotation. Which graph shows the image, triangle P’Q’R’? On a coordinate plane, triangle P prime Q prime R prime has points (negative 3, negative 1), (negative 3, negative 3), (negative 6, negative 2).

On a coordinate plane, triangle P prime Q prime R prime has points (negative 1, 3), (negative 3, 3), (negative 2, 6).

On a coordinate plane, triangle P prime Q prime R prime has points (1, negative 3), (3, negative 3), (2, negative 6).

On a coordinate plane, triangle P prime Q prime R prime has points (3, negative 1), (3, negative 3), (6, negative 2).

x=0

step-by-step explanation:

step-by-step explanation:

duck you

explanation:

remove parenthesis:

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apply rule

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multiply fractions:

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divide:

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mordancy.

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.