Your school roof is made of four trapezoids. Two of them have the bases of 14 m and 6 m respectively with the 8 m height. The remaining two have the bases of 12 m and 10 m with 6m height. How much roof material is needed to cover the roof?

292 m² of roof material is needed to cover the roof.

Step-by-step explanation:

In order to find how much roof material is needed to cover the roof, we must find the total amount of the area of the roof.

Because the roof is made of 4 trapezoids, we must use the formula:

Area= [(A+B)/2] × H

A and B represents the two parallel lines while H represents the height.

In order to solve the equation, you must use the Order of Operations, PEMDAS.

P= Parenthesis

E= Exponents and roots

M= Multiplication

D= Division

A= Addition

S= Subtraction

(If there is a parenthesis inside a parenthesis. Start by simplifying the parenthesis in the inside).

So:

A.The first set of two trapezoids

Area = [(14 + 6)/2] × 8

= [(20)/2] × 8

= 10 × 8

= 80 m²

One trapezoid is equal to 80 m². In order to find the total amount of both trapezoids, multiply the amount by 2.

So: 80 × 2= 160 m²

The total amount of both trapezoids is 160 m².

B.The second set of two trapezoids

Area= [(12 + 10)/2] × 6

= [(22)/2] × 6

= 11 × 6

= 66 m²

One trapezoid is equal to 66 m². In order to find the total amount of both trapezoids, multiply the amount by 2.

So: 66 × 2= 132 m²

The total amount of both trapezoids is 132 m².

Last step is to add both amounts in order to know the total amount needed of roof material that covers the roof.

So: 160 + 132= 292 m²

So the amount of roof material needed to cover the roof is 292 m².

I hope this helps! I'm sorry if its wrong or too complicated.

(-5,-28)

i graphed to on desmos.