Suppose a police officer is 1/2 mile south of an intersection, driving north towards the intersection at 45 mph. At the same time, another car is 1/2 mile east of the intersection, driving east (away from the intersection) at an unknown speed. The officer's radar gun indicates 25 mph when pointed at the other car (that is, the straight-line distance between the officer and the other car is increasing at a rate of 25 mph). What is the speed of the other car? Now suppose that the officer's radar gun indicates -25 mph instead (that is, the straight-line distance is decreasing at a rate of 25 mph). What is the speed of the other car this time?

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

no ,sorry if you needed it but you can ask and try to see if any one will anwser ,

step-by-step explanation:

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have a nice day

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles