What are the coordinates of the vertex of the parabola y=x^2+2x-1

Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).

Therefore, the vertex of y =  (x + 1)^2 - 2 is (-1, -2)