De un grupo de fichas numeradas del 1 al 15, ¿cuál es la probabilidad de elegir una ficha al azar y que esta sea par y múltiplo de 3?

2/15

Step-by-step explanation:

Comenzaremos escribiendo el número de mosaicos. Esto se ilustra a continuación:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15.

A continuación, escribiremos el múltiplo de 3. Esto se ilustra a continuación:

3 × 1 = 3

3 × 2 = 6

3 × 3 = 9

3 × 4 = 12

3 × 5 = 15

Por tanto, los múltiplos de 3 son:

3, 6, 9, 12 y 15

A continuación, determinaremos el número par entre 3, 6, 9, 12 y 15

Esto se ilustra a continuación:

NOTA: Los números pares son divisibles por 2 sin residuo.

3/2 = 1,5

6/2 = 3

9/2 = 4,5

12/2 = 6

15/2 = 7,5

Por tanto, los números pares son: 6 y 12

Finalmente, determinaremos la probabilidad de elegir una loseta par y múltiplo de 3. Esto se puede obtener de la siguiente manera:

Espacio muestral (S) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}

nS = 15

Par y múltiplo de 3 (E) = {6,12}

nE = 2

Probabilidad de elegir una loseta par y múltiplo de 3, P (E) =?

P (E) = nE / nS

P (E) = 2/15

Por lo tanto, la probabilidad de elegir una loseta par y múltiplo de 3 es 2/15

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step-by-step explanation:

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: