use point slope form to write an equation of the line with the given slope that passes through the given point.

A. y - 0 = 2 ( x + 2 )

Step-by-step explanation:

First you have to isolate y, by using A, the 0 can simply be forgotten about. Next, you must expand the equation, thus with 2 ( x + 2 ), it expands to:

y = 2x + 4

With this in mind, the b value is 4, and with a slope of 2, you can see that the equation eventually crosses the y-axis at 4.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.