What is the equation of the line that is perpendicular to y=-2/3x+4 and that passes through (-2,-2)?

Perpendicular lines have negative reciprocal slopes. So the slope of the line we are looking for is 3/2 since that is the negative reciprocal of -2/3. So far we know that our line will have the equation y = 3/2x +b. The line has to pass through the point (-4,2) so we can use that to find b:

2 = (3/2)*-4 + b

2 = -6 + b

8 = b

Now we can write the equation of the perpendicular line as:

y = (3/2)x + 8

is should be y = 5x

step-by-step explanation:

correct me if im wrong

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step-by-step explanation: