Mathematics, 26.10.2020 18:00 zetrenne73
Find the surface area of the part of the sphere x2+y2+z2=25 that lies above the cone z=x2+y2‾‾‾‾‾‾‾√
Answers: 1
square unit
![A=-25\int_{\theta=0}^{2\pi}[cos\phi]^{\pi/4}_{0} d\theta](/tpl/images/0840/5920/611a3.png)
![A=-25(1/\sqrt{2}-1)[\theta]^{2\pi}_{0}](/tpl/images/0840/5920/13849.png)
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Find the surface area of the part of the sphere x2+y2+z2=25 that lies above the cone z=x2+y2‾‾‾‾‾‾‾√...
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