If an investment account starts with $3900, and grows with 2.1% interest, compounded continuously. How much is the account worth after 10 years? Round your answer to the nearest dollar. Do NOT round until you have calculated the final answer.

If they are asking amount it is $4800.893013; $4800 (nearest dollar)

If they are asking the amount for interest is $900.8930129; $900 (nearest dollar)

Step-by-step explanation:

Compound interest Formula:

Amount = principle( 1+ rate/100)^n

Information from the question.

-So how you put it is the principle is $3900; the rate is 2.1%; the n is 10.

How to apply it?

- Just substitute in the values;

Amount=3900(1+2.1/100)^10

=4800.893013

~4800 ( nearest dollar)

》That is for amount.

Interest=4800.893013-3900

=900.893013

~900 ( nearest dollar)

》That is for interest.

Hope it helps:))

22 and 22

step-by-step explanation:

10 plus 12 equals 22.

12 plus 10 also equals 22 because regardless of what order they're in, they're gonna equal the same thing.

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42