approximately 6.9 million wrecked car are recycled in two consecutive years these were 500,000 more recycled the second year than the first year how many are recycled each year

Let's define the variables:

F = number of cars recycled the first year.

S = numbers of cars recycled the second year.

Then:

"approximately 6.9 million wrecked car are recycled in two consecutive years"

This can be written as:

F + S = 6,900,000

"... were 500,000 more recycled the second year than the first year"

S - F = 500,000

Then we have a system of equations:

F + S = 6,900,000

S - F = 500,000

To solve it, the first step is to isolate one of the variables in one of the equations, let's isolate S in the second equation:

S = 500,000 + F

Now let's replace it in the first equation:

F + (500,000 + F) = 6,900,000

2*F = 6,900,000 - 500,000 = 6,400,000

F = 6,400,000/2 = 3,200,000

S = 3,200,000 + 500,000 = 3,700,000

Then in the first year there are 3,200,000 cars recycled, and in the second year there are 3,700,000 cars recycled.

answdf

step-by-step explanation: bcuz d is right

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: