Let O be the point of intersection of the diagonals of quadrilateral ABCD. Prove that ABCD could be a trapezoid (has one pair of opposite sides parallel), if AAOD=ABOC.

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.

the correct answer is c

-1/3(x+1)^5

i’m pretty sure this is correct

720 oranges were in the shipment.