The Warriors scored 58 points in a recent basketball game. The team scored some 3 - point shots and some 2 - point shots. A total of 28 shots were successful. By surprise, no fouls were called so there were no 1 - point free throws were made. Write a system of equations that you would use to determine how many 3-point shots and how many 2-point shots were made.

The system of equations are;

x + y = 28

2x + 3y = 58

where x is the number of two points shot and y is the number of three points shot

Overall;

There are 26 2-points shot and 2 3-points shot

Step-by-step explanation:

Let the number of two points shot be x and the number of three points shot be y

Since there are a total of 28 shots with two and three points alone, then we can have;

x + y = 28. •••••••••(i)

The total number of points from 2 points shots will be 2 * x = 2x

The total number of points from 3 points shots will be 3 * y = 3y

We have the total number of points as 58;

Thus;

2x + 3y = 58 •••••••••(ii)

We can now proceed to solve this;

From i, x = 28 - y

insert this into ii

2(28-y) + 3y = 58

56 - 2y + 3y = 58

56 + y = 58

y = 58-56

y = 2

Recall;

x + y = 28

x + 2 = 28

x = 28-2

x = 26

w'x is 0.

hope it

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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