An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation of all components is 2.2 mm, how many of these components should she consider to be 80% sure of know the mean will be within 0.3 mm? Group of answer choices 1080 126 10 80 Way more than any of these answers

The correct option is;

80

Step-by-step explanation:

The standard deviation of the components = 2.2 mm

The difference in the mean = 0.3

The level of confidence (power)= 80%

The formula for finding the sample size is given as follows;

Where;

μ₁ - μ₂ = Is the difference in the mean = 0.3

a = The α multiplier = 0.05

b = The power multiplier = 0.8

σ = The standard deviation

n = The sample size

By substituting in the values, we have;

n ≈ 8

Rounding up to the next 10th gives;

n = 80

Therefore, the correct sample size should be about 80

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°