What is the equation of the line that is parallel to the line defined by the equation y = 2x + 4 and goes through the point (3, 2)?

Step-by-step explanation:

Hey there!

Given;

y = 2x + 4(i)

The point is; (3,2). The equation of line which passes through this point is;

(y-y1) = m2(x-x1)

(y-2)= m2(x-3)(ii)

From equation (i).

y = 2x+4

Comparing the equation with y = mx+c, we get;

Slope (m1)= 2

As per the condition of parallel lines, (m1=m2).

Therefore, m2= 2.

Now, keeping the slope of m1 in eqaution (ii)

(y-2)= 2(x-3)

y - 2 = 2x - 6

y = 2x -4

Therefore, the equation is y = 2x - 4.

Hope it helps...

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.