(1-sin^2 θ/1-cos^2 θ) (tanθ) = ?
a. tanθ
b. sinθ
c. cotθ
d. cosθ
e. secθ

A

Step-by-step explanation:

Hopefully this helps!

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet