How do you do this question?

Conditionally convergent

Step-by-step explanation:

Use alternating series test.

bₙ = n / √(n³ + 9)

lim(n→∞) bₙ

= lim(n→∞) [n / √(n³ + 9)]

= lim(n→∞) (n / √n³)

= lim(n→∞) (1 / √n)

= 0

The limit is 0, and bₙ is a decreasing series, so ∑aₙ converges.

Since bₙ > 1/n for n > 2, and 1/n diverges, ∑bₙ diverges.

(Alternatively, we could use limit comparison test to compare bₙ to n/√n³ and show that both diverge.)

Therefore, ∑aₙ is conditionally convergent.

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value