What is the value of min the figure below? In this diagram, AABD ABCD. 8
m
C
A. 136
B. 572
C. 32
Ο Ο Ο
D. V632
E. 147
o
F. 274
HELP

Choice A) sqrt(136)

This is equivalent to 2*sqrt(34)

Explanation:

First let's find BD

The three triangles are similar, allowing for the proportion to be set up

AD/BD = BD/DC

9/x = x/8

9*8 = x*x

x^2 = 72

x = sqrt(72)

BD = sqrt(72)

Now we can use the pythagorean theorem. Focus on triangle BDC.

The legs are BD = sqrt(72) and DC = 8. Let's find the hypotenuse

(BD)^2 + (DC)^2 = (BC)^2

(sqrt(72))^2 + (8)^2 = m^2

72 + 64 = m^2

136 = m^2

m^2 = 136

m = sqrt(136)

We can simplify this but your teacher has chosen not to. If you want to simplify, then,

m = sqrt(136)

m = sqrt(4*34)

m = sqrt(4)*sqrt(34)

m = 2*sqrt(34)

In the first triangle 80+20+p=180 (since sum of all angles of a triangle is 180)so p= 80also in second triangle 55+45+q=180 (since sum of all angles of a triangle is 180)so q=80so we can conclude that p=80 degrees q=80 degrees so p=q=80 degreeshence option b is correct

Im not that good with division but i think 5 is -6but dont quote me on thatim not the best in division but thats my answer