What is the range of this quadratic function?

(negative infinity, 4]

Step-by-step explanation:

Reminder: the range is all the possible y values the function can get by plugging in x values.

Since this is a downward opening parabola, it won't have a lower boundary, which means that the answer must be (negative infinity, 4]

We can further check that's correct by seeing that the parabola has its vertex at 4, which is written in the answer.

That means the correct answer must be (negative infinity, 4]

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.