WILL GIVE BRAINLIEST! For ΔABC with A(–5, –4), B(3, –2), and C(–1, 6), M is the midpoint of AB and N is the midpoint of BC. Show that MN = 1/2AC. What is the length of MN and AC?

length of MN is √5 units

length of AC is 2√5 units

Step-by-step explanation:

Here, we want to calculate the coordinates of both midpoints

Mathematically, formula midpoint coordinates are;

(x,y) = (x1 + x2)/2 , (y1 + y2)/2

For AB , coordinates M are as follows

(-5+3)/2,(-4-2)/2 = (-1,-3)

For MN , coordinates of N will be;

(3-1)/2, (-2-6)/2 = (1, -4)

To calculate the distance between two points, we use the formula below;

D = √(x2-x1)^2 + (y2-y1)^2

So for MN ((-1,-3) and (1,-4)

Distance will be

D = √(2^2 + (-1)^2 = √5

For AC, we have

D = √(-4)^2 + (-2)^2 = √20 which is same as 2 √5

MN = √5

AC = 2 √5

Thus;

MN = 1/2 AC

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.