Algebraically, an ordered pair is a solution to a system of two linear inequalities if and only if it . A.
makes both the top and bottom inequalities false
B.
makes the top inequality true and the bottom inequality false
C.
makes the top inequality false and the bottom inequality true
D.
makes both the top and bottom inequalities true

D.  Makes both the top and bottom inequalities true

Step-by-step explanation:

System of linear inequalities

Consider these two inequalities:

2x+3y > 20

3x-2y > 5

The solution of the system consists of all the ordered pairs (x,y) that satisfy both inequalities. The ordered pair (3,5) makes the first inequality true because

2*3+3*5=21 and it's effectively greater than 20.

But that pair makes the second inequality false, since

3*3-2*5=-1 is not greater than 5.

Thus, the pair (3,5) is not part of the solution.

If we test the pair (6,2), we'll check both inequalities are true, thus (6,2) is part of the solution.

Thus, the correct answer to the question is

D.  Makes both the top and bottom inequalities true

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation:

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: