Could ΔJKL be congruent to ΔXYZ? Explain. Yes, if JL ≅ XZ. Yes, if XZ = 10. No, because the hypotenuse of one triangle is equal in length to the leg of the other triangle. No, because the leg of one triangle is equal in length to the leg of the other triangle.

The answer is "No since one triangle's hypotenuse is equivalent in length to the triangle's leg".

Step-by-step explanation:

When its corresponding sides are congruent, there may be two triangles. Here a leg of the ΔXYZ measurements 10 (XY = 10). So, it must calculate upwards of 10 on its hypotenuse (the biggest hand in a rectangle hand).  

The two triangle hypotenuse is different: hypotenuse ΔJKL the measures of the hypotenuse are hypotenuse of = (KL=10). The hypotenuse of ΔXYZ the measures of the hypotenuse is greater than ten (YZ>10), that's why it's not compatible and the triangles were not compatible.

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