Mike has discovered that the pool in his backyard is leaking slowly. The pool holds 14,102 gallons of water, and is leaking at a rate of 7 gallons per day. If mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the pool after 169 days?

12,919 gallons of water will remain in the pool after 169 days .

Step-by-step explanation:

Given: Initial quantity of water = 14,102 gallons

Water leaking rate = 7 gallons per day

Water remains in pool after d days = ( Initial quantity of water) -(water leaking rate) (Number of days)

= 14102 - 7d

At d= 169

Water remains in pool after 169 days  = 14102 - 7(169)

= 14102 - 1183

= 12919

Hence, 12,919 gallons of water will remain in the pool after 169 days .

what are the things "represented below"?

step-by-step explanation:

nobody can if you dont give the choices

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions