As a fitness instructor you train people who have never run before As a fitness instructor you train people who have never run before to complete and 5 km race is one of your clients completed her first 5 km race and 36 minutes 15 seconds she completes her next 5 km race in 10 weeks later and 31 minutes 55 seconds what is the change in rate

Step-by-step explanation:

The question is not properly presented, nevertheless, we can wrap our heads around it.

Firstly, let us solve for the initial speed

given

distance= 5km

time taken= 36 min 15 seconds

time= 36.25min to hours 0.60hours

speed= distance/time

speed= 5/0.6

speed= 8.3 km/h

10 week later

distance= 5km

time taken= 31 min 55 seconds

time= 36.91min to hours 0.62hours

speed= distance/time

speed= 5/0.62

speed= 8.1 km/h

Therefore the change in rate(speed) is =8.3-8.1= 0.2km/h

0.31 m/s

Step-by-step explanation:

First race :

Distance = 5km = (5 * 1000) = 5000 meters

Time taken = 36 minutes, 15 seconds = (36*60) + 15 = 2,175 seconds

Speed rate = distance / time

Rate = 5000 / 2175

= 2.298

= 2.3 ms^-1

2nd race :

Distance = 5km = (5 * 1000) = 5000 meters

Time taken = 31 minutes, 55 seconds = (31*60) + 55 = 1,915 seconds

Speed rate = distance / time

Rate = 5000 / 1915

= 2.298

= 2.61 ms^-1

Change in rate : (2nd race speed - 1st race speed)

= (2.61 - 2.30) m/s

= 0.31 m/s

= (0.31 / 1000)km * 3600 = 1.116 kmh

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6