If P1 is (3,-3) and the midpoint is (-2,1), what are the points of P2?

Step-by-step explanation:

Hey there!

The points P1(3,-3) and midpoint is (-2,1). Let (X,y) be the end point.

Note: Find through using midpoint formula.

midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )

Put all values.

(\frac{X+3}{2},\frac{-3+y}{2})

Since they are equal, equating with it's corresponding components.

\frac{3 + x}{2} = - 2

-2 = 3 + x

-4 -3= x

Therefore, X= -7.

Now,

Therefore, y= 5

Therefore, the other end point is (3,5).

Hope it helps...

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents