Suppose that the revenue generated by selling x units of a certain commodity is given by R = -1/5x^2 + 200x. Assume that R is in dollars. What is the maximum revenue possible in this situation?

Answer

50,000

Step by step

y=ax^2+bx+c

use formula x=-b/2a to find maximum/ minumum point with quadratic formulas

x=-200/-1/5(-0.2)

x=500

plug in 500 for x

-1/5(500)^2+200(500)

-50000+1000000

500000

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2

there are infinitely many solutions.