An object is thrown off a 256-foot-tall building, and the distance of the object from the ground is measured every second. The function that models the height, h, of the object after t seconds is h(t) = –16t2 + 96t + 256. Determine the time when the object hits the ground

The object hits the ground 8 seconds after launch.

Step-by-step explanation:

Let , where is the height of the object above the ground, measured in feet, and is time, measured in seconds. We notice that given expression is a second-order polynomial and hence, there are two roots, one of them corresponding to the instant when the object hits the ground. If , we get the following expression:

(Eq. 1)

Roots are found by applying the Quadratic Formula:

or

Only the first root offer a solution that is physically reasonable. Thus, the object hits the ground 8 seconds after launch.

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct

ok

step-by-step explanation: