The perimeter of the triangle is 6a + 3 units. Write an expression in simplest form for the length of Side 3.

The length of the third side is a-2.

Given that:

Perimeter of triangle: 6a + 3

Length of first side: 2(a+3)

Length of second side: 3a -1

Let the length of the third side of the triangle be x.

Then as perimeter of a triangle is sum of lengths of all 3 sides of the triangle, thus we have:

Thus we have length of the third side as a -2.

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Side 3 = a - 2

Step-by-step explanation:

Perimeter of a ∆ = sum of all the sides of a triangle

Perimeter of the given ∆ = 6a + 3 units

Side 1 = 2(a + 3)

Side 2 = 3a - 1

Side 3 = ?

Therefore:

Side 3 = Perimeter - sum of side 1 and 2

Thus:

Side 3 = 6a + 3 - [2(a + 3) + (3a - 1)]

Side 3 = 6a + 3 - [2a + 6 + 3a - 1]

Side 3 = 6a + 3 - [5a + 5]

Side 3 = 6a + 3 - 5a - 5

Side 3 = a - 2

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

its a straight line parallel to the time axis