The National Fire Protection Association reported that house fires in the United States result in $6.8 billion in losses annually (National Fire Protection Association, September 2015). Suppose a random sample of 50 house fires in San Antonio yields a mean loss of $18,503. If the population standard deviation is s 5 $3300, what is the margin of error for a 95% confidence interval

914.7

Step-by-step explanation:

The Formula for Margin of Error =

z × standard deviation/√n

From the above question,

z score for 95% confidence interval = 1.96

Standard deviation = $3300

n = random sample = 50

Margin of Error = 1.96 × 3300/√50

= 1.96 × 466.69047558

= 914.71333214

Margin of Error ≈ 914.7

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

160

step-by-step explanation:

idk

i hope i