If a sample of 6 keyboards is randomly selected, what is the probability that at least 5 of these will have a mechanical defect

0.1978 is the probability that at least 5 keyboards will have mechanical defect.

Step-by-step explanation:

Solution:

Given:

A repair facility has 25 failed keyboards.

10 keyboards have electrical defect.

15 of which have mechanical defect.

Randomly selected keyboard= 6

The set of A is the set of keyboards with electrical defect.

And  the set of B is set of keyboards with mechanical defect.

N(A U B) = n (A) + n(B) – n (A ∩B)

Probability of at least 5 will have mechanical defect is:

                              = p(  5 mechanical defect  U 6 mechanical defect)

                              = p(5 mechanical defect  ) + p(6 mechanical defect)

                                =(15 C 5 x 10 C1 + 15 C6 X 10C0) / 25 C6

                                = 3003 X 10 / 177100 + 5005 X 1 / 177100

                                = 30030 + 5005 / 177100

                               = 35035 / 177100

                              = 0.1978

0.1978 is the probability that at least 5 keyboards will have mechanical defect.

the answer is 48m^2!

step-by-step explanation:

answer: x=3 and y=4

step-by-step explanation: