Use the third pair of points to do each of the following. The third pair is (-6, 7), (-3, -4). 1. Give the slope
2. Write the equation in point-slope form.
3. Write the equation in slope-intercept form.
4. Write the equation of the line in standard form.
5. Give the x-intercept from standard form (remember, let y=0)
6. Give the y-intercept from standard form (remember, let x=0)

The slope of the line is  m = −11/3 ≈ −3.66666666666667 .

Step-by-step explanation:

The slope of a line passing through two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.

We have that x1=−6, y1=7, x2=−3, y2=−4.

Plug the given values into the formula for a slope: m=−4−(7)−3−(−6)=−113.

Now, the y-intercept is b=y1−mx1 (or b=y2−mx2, the result is the same).

b=7−(−113)(−6)=−15

Finally, the equation of the line can be written in the form y=b+mx:

y=−15−11x3

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8