The temperature at 5:00 a. m. was –6 °F. By 3:00 p. m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p. m. decreased from the high by latex of the change in temperature in Fahrenheit degrees from 5:00 a. m. to 3:00 p. m., what was the temperature at 8:00 p. m.?

Complete question :

The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?

-6°F

Step-by-step explanation:

Temperature at 5am (t1) = - 6°F

Temperature at 3pm (t2) = 36°F

Change in temperature, between 5am and 3pm:

(t2 - t1) = (36 - (-6)) = (36 + 6) = 42°F

Hence, temperature at 8:00 pm:

High temperature - change in temperature between (5am - 3pm)

36°F - 42°F = - 6°F

d. vertex

step-by-step explanation:

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm