Scientists want to estimate the mean weight of mice after they have been fed a special diet. From previous studies, it is known that the weight is normally

distributed with standard deviation 4 grams. How many mice must be weighed so

that a 95% confidence interval will have margin of error of 0.4 grams?

Write only an integer as your answer.

n = 484

Step-by-step explanation:

If Confidence Interval  CI = 95 %   then α = 5%  and α/2 = 2,5 %

α/2 = 0,0125

MOE for normal distribution is:

MOE = z * σ/√n

For α/2 = 0,0125    ⇒ z(score) = -2,2

MOE = |-2,2| * 4/√n

0,4*√n = 8,8

√n = 8,8 / 0,4

√n = 22

n = 484

rick would give her the best deal as he will charge $8.88 per hour

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest