Mathematics, 22.10.2020 16:01 steven2669
Suppose that a tea company estimates that its monthly cost is C(c) = 500x² + 100x and its monthly revenue is R(2) = -0.6x3 + 700x2 – 400x + 300, where x is in thousands of boxes of tea sold. The profit is the difference between the revenue and the cost. What is the profit function, p(X)?
O A. P(x) = 0.6x3- 200x2 + 500x+ - 300
OB. P(x) = -0.6x3 + 1200x2 – 300x + 300
O C. P(x) = -0.6x3 + 200x2 – 500x + 300
D. P(xl = 0.6x3 + 200x2 – 500x + 300
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Suppose that a tea company estimates that its monthly cost is C(c) = 500x² + 100x and its monthly re...
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