A(n)=2+(n-1)(3) find the fourth and tenth term of the sequence

The fourth term is 11 and the tenth term is 29

Step-by-step explanation:

Let us use the given formula to solve the question

∵ A(n) = 2 + (n - 1)(3) is the formula of the nth term of an sequence

∵ n is the position of the term in the sequence

∴ For the fourth term n = 4

∴ For the tenth term n = 10

→ Substitute n by 4 in the formula above to find the fourth term

∵ A(4) = 2 + (4 - 1)(3)

∴ A(4) = 2 + (3)(3)

∴ A(4) = 2 + 9

∴ A(4) = 11

∴ The fourth term is 11

→ For the tenth term put n = 10

∵ n = 10

∵ A(10) = 2 + (10 - 1)(3)

∴ A(10) = 2 + (9)(3)

∴ A(10) = 2 + 27

∴ A(10) = 29

∴ The tenth term is 29

sup

step-by-step explanation:

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !