Find (f+g)(x) and (f - g)(x) for f(x) = 6x² + 5 and g(x) = 3 – 9x. O (f+g)(x) = 6x²-9x +8
(f-g)(x) = 6x²+9x +2

O (f+g)(x) = 6x² + 9x + 2
(f-g)(x) = 6x²-9x +8

O (f + g)(x) = 6x4 - 4x + 3
(f-g)(x) = 6x² + 14x - 3

O (f+g)(x) = 6x² + 9x - 8
(f-g)(x) = 6x² - 9x + 2

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: