You invested 26,000 in two accounts paying 7% and 8% annual interest, respectively. if the total interest earned for the year is $1840, how much was invested at each rate

0.08x + 0.09y = 1700,     where x is the amount that has 8% interest

                                               y is the amount that has 9% interest

                              equation (1)

x+y = 19000

x = 19000 - y ,         equation   (2)

substitute (2) into (1):

0.08(19000 - y) + 0.09y = 1700

1520-0.08y+0.09y = 1700

so, y = 18000

x = 19000-y=1000

(1000,   18000) is the answe

Step-by-step explanation:

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