A i think
Step-by-step explanation:
1 Multiply both sides by 3x3x.
6{x}^{2}-12+21x=x6x
2
β12+21x=x
2 Move all terms to one side.
6{x}^{2}-12+21x-x=06x
2
β12+21xβx=0
3 Simplify Β 6{x}^{2}-12+21x-x6x
2
β12+21xβx Β to Β 6{x}^{2}-12+20x6x
2
β12+20x.
6{x}^{2}-12+20x=06x
2
β12+20x=0
4 Use the Quadratic Formula.
x=\frac{-20+4\sqrt{43}}{12},\frac{-20-4\sqrt{43}}{12}x=
12
β20+4β
43
,
12
β20β4β
43
5 Simplify solutions.
x=-\frac{5-\sqrt{43}}{3},-\frac{5+\sqrt{43}}{3}x=β
3
5ββ
43
,β
3
5+β
43