Solve the problems. Write the complete proof in your paper homework and for online (only) respond to questions or statements (if any) that are parts of your proof or related to it. Prove:
BC ∥ AD

huh? im pretty sure it is in 199

step-by-step explanation:

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gimmee one of those gold crowns!

~coco

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

need more info

step-by-step explanation:

what do you mean by "representation"? graph? table? etc.