Help please I beg you

The first-serve percentage of a tennis player in a match is normally distributed with a standard deviation of 4.3%. if a sample of 15 random matches of the player is taken, the mean first-serve percentage is found to be 26.4%. what is the margin of error of the sample mean? a. 0.086% b. 0.533% c. 1.11% d. 2.22%

Solve for n? [tex]z = \frac{3}{4} mn[/tex]

Drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. match each division expression with the correct quotient.