What are the solutions of 3x2 + 14x + 16 = 0?

x=− 3/8

x=−2.667

x=−2

4.3     Solving    3x2+14x+16 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     3

                     B   =    14

                     C   =   16

Accordingly,  B2  -  4AC   =

                    196 - 192 =

                    4

Applying the quadratic formula :

              -14 ± √ 4

  x  =    —————

                   6

Can  √ 4 be simplified ?

Yes!   The prime factorization of  4   is

  2•2  

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 4   =  √ 2•2   =

               ±  2 • √ 1   =

               ±  2

So now we are looking at:

          x  =  ( -14 ± 2) / 6

Two real solutions:

x =(-14+√4)/6=(-7+)/3= -2.000

or:

x =(-14-√4)/6=(-7-)/3= -2.667

Hope this helps! Please mark Brainliest!

-2 or -8/3

Step-by-step explanation:

It factors as: (3x+8)(x+2)

so x can equal -2 or -8/3

answer: 19 is   2

step-by-step explanation: i just looked at your answer and wrote it down