Which steps can be used to verify that tan(w + Pi) = tan(w)? Rewrite tan(w + Pi) as tan(w) + tan(Pi). Then simplify the expression using tan(Pi) = 1. Rewrite tan(w + Pi) as tan(w) + tan(Pi). Then simplify the expression using tan(Pi) = 0. Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 1. Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0.

The given expression can be prove by using tangent sub-identity. In the solution we will use sub-identity.

The correct option is Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0.

Given:

The given expression is as follows,

Write the tangent sub-identity.

Now replace with and with .

Substitute 0 for  .

Thus, the correct option is Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0.

Learn more about tangent sub-identity here:

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Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0

Step-by-step explanation:

According to tangent sub identity

Tan(A+B) = TanA+TanB/1-tanAtanB

Applying this in question

Tan(w+Pi) = tan(w)+tan(pi)/1-tan(w)tan(pi)

According to trig identity, tan(pi) = 0

Substitute

Tan(w+Pi) = tan(w)+0/1-tan(w)(0)

Tan(w+Pi) = tan(w)/1

Tan(w+Pi) = tan(w) (proved!)

Hence the correct option is

Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0

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