1. During October, William Korth worked 160 regular time hours at $9.28 an hour and 18 overtime hours at time- and-a-half. What is William’s gross pay for October?

2. Last year, Ida Zolen worked 2,000 hours at regular time pay of $8.20 an hour. She also worked 75 hours over time

at double his regular rate. What was Ida’s gross pay last year?

3. Alan Kirbaum works on an 8-hour day basis and is paid $8 an hour for regular time work and time-and-a half for

overtime work. Last week he worked these hours: Monday:9 ; Tuesday:6 ; Wednesday:11 ; Thursday:8 ; Friday:9.

A) How many regular hours did he work?

B) How many overtime?

C) What is his overtime rate?

D) What is his overtime pay?

E) Find Alan’s gross pay.

4. Stephen Woll’s regular pay is $20 an hour. He is paid time and a half for overtime work beyond 40 hours a week. He

worked: Monday:11 ; Tuesday:10 ; Wednesday:10 ; Friday:12. Find Stephen

Kindly check explanation

Step-by-step explanation:

1.) regular time hours = 160

Overtime hours = 18

Gross pay = (9.28 * 160) + (1.5 * 9.28 * 18) = $1735.36

2.) Last year, Ida Zolen worked 2,000 hours at regular time pay of $8.20 an hour. She also worked 75 hours over time at double his regular rate. What was Ida’s gross pay last year?

Gross pay:

(2000 * 8.20) + (2 * 8.20 * 75) = $17,630

3. Alan Kirbaum works on an 8-hour day basis and is paid $8 an hour for regular time work and time-and-a half for overtime work. Last week he worked these hours: Monday:9 ; Tuesday:6 ; Wednesday:11 ; Thursday:8 ; Friday:9.

A) How many regular hours did he work?

Regular hours = (8 + 6 + 8 + 8 + 8).= 38 hours

B) How many overtime?

Overtime = (1 + 3 + 1). = 5 hours

C) What is his overtime rate?

2.5 * $8 = $20

D) What is his overtime pay?

$20 * 5 = $100

E) Find Alan’s gross pay.

(38 * $8) + $100 = $404

4. Stephen Woll’s regular pay is $20 an hour. He is paid time and a half for overtime work beyond 40 hours a week. He

worked: Monday:11 ; Tuesday:10 ; Wednesday:10 ; Friday:12. Find Stephen

Total Hour = (11 + 10 + 10 + 12) = 43 hours

597

step-by-step explanation:

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)