A plane takes off from a runway and begins its climb. The plane takes off at a constant acceleration of 20 LaTeX: m /s^{2} . Once it reaches altitude it moves at 246 m/s, and maintains that speed. If it continues at this speed for 93 min, how far would the plane have traveled from the time took off?

The plane have traveled 1512.9 m from the time took off

Step-by-step explanation:

Acceleration

Initial speed = u = 0

Final speed = v = 246 m/s

Time = t = 93

We are supposed to find how far would the plane have traveled from the time took off

We will use equation of motion

Hence The plane have traveled 1512.9 m from the time took off

a

b

d

step-by-step explanation:

16.80 times .20= 3.36

step-by-step explanation: