According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. (Round your answers to 4 decimal places where possible) a. Compute the probability that a randomly selected peanut M&M is not green. 0.850 b. Compute the probability that a randomly selected peanut M&M is green or red. c. Compute the probability that two randomly selected peanut M&M’s are both red. d. If you randomly select two peanut M&M’s, compute that probability that neither of them are red e. If you randomly select two peanut M&M’s, compute that probability that at least one of them is red.

Complete question

The complete question is shown on the first uploaded image

a

b

c

d

e

Step-by-step explanation:

From the question we are told that

   The proportion of M & M's that is  brown is  b =  0.12

   The proportion of M & M's that is  yellow  is  y =  0.15

    The proportion of M & M's that is  red  is  r =  0.12

    The proportion of M & M's that is  blue  is  b =  0.23

    The proportion of M & M's that is  orange  is  o =  0.23

    The proportion of M & M's that is  green  is  g =  0.15

Generally the probability that a random selected M&M is not yellow is  

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Generally the probability that a randomly selected peanut M&M isgreen or red is mathematically represented as

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Generally the  probability that two randomly selected peanut M&M’s are both red is mathematically represented as

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Generally if two  two peanut M&M’s are selected the probability that neither of them are red is mathematically represented as

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Generally if two  two peanut M&M’s are selected the probability that at least one of them is red is mathematically represented as

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75%

step-by-step explanation:

7

step-by-step explanation: