What is the solution to the system of equations? 3x+10y=-47
5x - 7y=40
O (1.-5)
O (1,5)
0 (-1,-5)
0 (-1,5)

x=1 ,y=-5

Step-by-step explanation:

3x + 10y = 47

5x - 7y = 40

21x + 70y = 329. equ 1

50x - 70y = 400. equ 2

subtract equ 1 from 2

=71x = 71

divide both sides by the 71

71/71 = 71/71

x = 1

to find y

substitute x into either equ 1 or equ 2

am using equ 2

5x - 7y = 40

5(1) - 7y = 40

5 - 7y = 40

7y = 5 - 40

7y = -35

divide both sides by the coffecient of y

7y/7 = -35/7

y = - 5

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square