Suppose is a function such that ′()=1/ for >0. Find an expression for the derivative of each function below: (a) ()=(^10)
(b) ()=(10)
(c) ℎ()=(1/)

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.

the square root of what number? if you add that, then someone will probably answer the question.

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation: