Jill counted 20 pigs and chickens in the farm. Jack counted a total of 54 legs for the animals. How many chickens were there in the farm?

Let the number of chickens in the farm = x

Let the number of pigs in the farm = y

Number of legs of chickens = 2*x (since chickens have 2 legs)

Number of legs of pigs = 4*y (since pigs have 4 legs)

We are given that there are a total of 20 animals (pigs + chickens)

so, number of chickens + number of pigs = 20

x + y = 20

We are given that there is a total of 54 legs in the farm

so, legs of chickens + legs of pigs = 54

2x + 4y = 54

Solving for number of chickens and pigs:

from the question, we have deduced that:

x + y = 20

2x + 4y = 54

taking the value of x from the first equation and using it in the second equation

x = 20 - y

2(20-y) + 4y = 54

40 - 2y + 4y = 54

40 + 2y = 54

2y = 14

y = 7

Using this value of y in the first equation:

x + y  = 20

x + (7) = 20

x = 13

Therefore, there are 13 chickens and 7 pigs in the farm

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.