Find the vertex of the function given below

vertex = (3, - 8 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

= -

y = x² - 6x + 1 ← is in standard form

with a = 1 and b = - 6 , thus

= - = 3

Substitute x = 3 into the function for y

y = 3² - 6(3) + 1 = 9 - 18 + 1 = - 8

vertex = (3, - 8 )

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6