Kelly is recording the temperature of a cooling chemical. Using the table, determine the initial temperature of the chemical when she poured into the beaker.

Initial temperature of the chemical = 97°

Step-by-step explanation:

Time             Temperature              Difference

4                          89.5                               -

10                        78.25              78.25 - 89.5 = -11.25

16                        67.00              67 - 78.25 = -11.25      

There is a common difference of -11.25 in each successive term.

Therefore, cooling of a chemical represents a linear function.

Let the function representing temperature is,

f(t) = at + b

Where 'a' = rate of change in temperature

b = initial temperature

t = time

Now 'a' = =

        a = -1.875

f(t) = -1.875t + b

For t = 4 and f(t) = 89.50,

89.50 = -1.875(4) + b

b = 97

Therefore, function representing the cooling of chemical is,

f(t) = -1.875t + 97

And the initial temperature of the chemical was 97° when it was poured into the beaker.

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step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm