Cecelia planted two bushes at the same time and measured their heights over several years. She represented each bush’s growth as shown. Bush A: Bush B: Had a height of 7.5 in. when planted; Grew at a constant rate of 2.5 in. per year Which of the following statements are true? Choose all that apply. A Bush A has a greater rate of change than Bush B. B Bush B has an initial value less than the initial value of Bush A. C After 7 years, Bush B was 1 inch taller than Bush A. D Bush B grows at a slower rate than Bush A. E Bush A and Bush B were the same height when planted.

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!